"our opponent has 5 dice.
You have 4 dice.
Current Bid At least three 3s
You Challenged Your Opponent's Bid! You lost the challenge. You lose a die."
My opponents dice: 6, 2, 3, 2, 3 My dice: 5, 5, 6, 1
There are only two 3s in play. My opponent bid at least three 3s. How did I lose that?
Edit: "Your opponent has 4 dice.
You have 2 dice.
Current Bid At least two 6s
You Challenged Your Opponent's Bid! You lost the challenge. You lose a die." Neither of us has a 6!
1's act as a wild card.
[edit] From the Rules:

You're welcome, I think said she is going to try to make the rules easier to understand sometime soon.

Yeah, but the 1's counting as wild cards doesn't explain this. He has only one 2, and no 1's.

The bid includes all dice in play, yours and your opponent's.
...0_o Oy vey...this is legitimately the most confusing game on subeta for me. ^_^; Thanks for the help though. goes to re-read rules again just in case she missed something else too

You're welcome~ I own a Liar's dice game from Pirates of the Caribbean, that's probably the only reason I understand it tbh
Yeah honestly I didn't get it until today. But when you start the game and it is your turn first, then you are able to select up to 10 dice on the first round. That is how I finally realized that it was counting both sides' dice.
Locking since this is not a bug.
Dexter by ❤